∣r1−r2∣=C1C2 for intersection ⇒r−3<5⇒r<8
and r1+r2>C1C2,r+3>5⇒r=2
From (1) and (2), 2<r<8.
If the two circles (x−1)2+(y−3)2=r2 and x2+y2−8x+2y+8=0 intersect in two distinct point, then
Held on 30 Apr 2003 · Verified 6 Jul 2026.
r>2
2<r<8
r<2
r=2
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