
$\begin{aligned}
& \mathrm{v}=\frac{4}{3} \pi \mathrm{r}^3 \
& \frac{\mathrm{dv}}{\mathrm{dt}}=4 \pi \mathrm{r}^2 \frac{\mathrm{dr}}{\mathrm{dt}} \
& 81=4 \pi \mathrm{r}^2 \times \frac{1}{4 \pi} \
& \mathrm{r}^2=81 \
& \mathrm{r}=9
\end{aligned}surfaceareaofchocolate=4 \pi(r-1)^2=256 \pi$