$\begin{aligned}
& a|x|=|y| e^{y x-\beta}, a, b \in N \
& x d y-y d x+x y(x d y+y d x)=0 \
& \frac{d y}{y}-\frac{d x}{x}+(x d y+y d x)=0 \
& \ell n|y|-\ell n|x|+x y=c \
& y(1)=2 \
& \ell n|2|-0+2=c \
& c=2+\ell n 2 \
& \ell n|y|-\ell n|x|+x y=2+\ell n 2 \
& \ell n|x|=\ell n\left|\frac{y}{2}\right|-2+x y \
& |x|=\left|\frac{y}{2}\right| e^{x y-2} \
& 2|x|=|y| e^{x y-2} \
& \alpha=2 \quad \beta=2 \quad \alpha+\beta=4
\end{aligned}$
Let α|x|=|y| e^x y-β, α, β ∈ N be the solution of the differential equation x ~d y-y ~d x+x y(x ~d y+y ~d x)=0, y(1)=2. Then α+β is equal to
JEE Main 2024 — Mathematics Calculus
Let α∣x∣=∣y∣exy−β,α,β∈N be the solution of the differential equation x dy−y dx+xy(x dy+y dx)=0, y(1)=2. Then α+β is equal to ________
Held on 8 Apr 2024 · Verified 6 Jul 2026.
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