Given:
y=f(x)=∣x−1∣+∣x−2∣
\Rightarrow f(x)={\begin{matrix}3-2x:x<1 1;1\leq x<2 \\ 2x-3;x\geq 2\end{matrix}
Let us draw diagram of y=f(x)&y=3 we get,
Required area is the area of trapezium which is
Area =21[1+3]×2
=4 sq. units
The area bounded by the curves y=∣x−1∣+∣x−2∣ and y=3 is equal to
Held on 6 Apr 2023 · Verified 6 Jul 2026.
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