Given,
f(x)=(x−3)n1(x−5)n2
Differentiating the function to get maxima and minima, we get
f′(x)=(x−3)n1−1(x−5)n2−1(n1+n2)(x−n1+n25n1+3n2)
Now checking the option, we get
Option (3) is incorrect since
for n1=3,n2=5
f′(x)=8(x−3)2(x−5)4(x−830)
minima at x=830.