If the absolute maximum value of the function f(x)=(x2−2x+7)e(4x3−12x2−180x+31)in the interval [−3,0] is f(α), then
Held on 25 Jul 2022 · Verified 6 Jul 2026.
α=0
α=−3
α∈(−1,0)
α∈(−3,−1)
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