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The position of a moving car at time t is given by f(t)=at^2+bt+c,t>0, where a,b andc are real numbers greater than 1. Then the average speed of the…

JEE Main 2020 — Mathematics Calculus

2020mcqeasy

The position of a moving car at time ttt is given by f(t)=at2+bt+c,t>0f(t)=a{t}^{2}+bt+c,t>0f(t)=at2+bt+c,t>0, where a,bandca,b\text{and}ca,bandc are real numbers greater than 111. Then the average speed of the car over the time interval [t1,t2][{t}_{1},{t}_{2}][t1​,t2​] is attained at the point:

Official previous-year question

Held on 6 Sept 2020 · Verified 6 Jul 2026.

Options

  1. A

    (t2−t1)2\frac{({t}_{2}-{t}_{1})}{2}2(t2​−t1​)​

  2. B

    a(t2−t1)+ba({t}_{2}-{t}_{1})+ba(t2​−t1​)+b

  3. C

    (t1+t2)2\frac{({t}_{1}+{t}_{2})}{2}2(t1​+t2​)​

  4. D

    2a(t1+t2)+b2a({t}_{1}+{t}_{2})+b2a(t1​+t2​)+b

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