Point of intersection of y={x}^{2}&y=-2x+3, is obtained by x2+2x−3=0⟹x=−3,1.

So, area of the required region is
∫−31((3−2x)−x2)dx
=[3x−x2−3x3]−31=332.
JEE Main 2020 — Mathematics Calculus
The area (in sq. units) of the region (x,y)∈R2:x2≤y≤3−2x, is.
Held on 8 Jan 2020 · Verified 6 Jul 2026.
332
334
329
331
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