dxdy=xx2−2y
⇒dxdy+x2y=x. It is in linear form.
I.F.=e∫x2dx=e2lnx=x2
∴y.x2=∫x.x2dx=4x4+c
∵At x=1,y=−2,
∴−2×12=4(1)4+c
⇒c=−2−41=−49
∴curve is y.x2=4x4−49
∴It passes through (3,0).
If a curve passes through the point (1,−2) and has slope of the tangent at any point (x,y) on it as xx2−2y, then the curve also passes through the point
Held on 12 Jan 2019 · Verified 6 Jul 2026.
(3,0)
(−1,2)
(−2,1)
(3,0)
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