Degree of f(x) will be 3
f(x)=ax3+bx2+cx+d
f(3x)=27ax3+9bx2+3cx+d
f′(x)=3ax2+2bx+c
f′′(x)=6ax+2b
f(3x)=f′(x)f′′(x)
Comparing the coefficient, we get
27a=18a2 ⇒a=23
Also b=0,c=0,d=0
f(x)=23x3, f(2)=12
⇒f′(x)=29x2,f′′(x)=9x
Hence, f′(2)=18,f′′(2)=18
Hence, f′′(2)−f′(2)=0