Given differential equation is dxdy+x2⋅y=x2 This is of the linear form. ∴P=x2,Q=x2 I.F =e∫x2dx=elogx2=x2 Solution is y⋅x2=∫x2⋅x2dx+c=5x5+cy=5x3+cx−2
JEE Main 2012 — Mathematics Calculus
The general solution of the differential equation dxdy+x2y=x2 is
Held on 19 May 2012 · Verified 6 Jul 2026.
y=cx−3−4x2
y=cx3−4x2
y=cx2+5x3
y=cx−2+5x3
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