Let A be the area, b be the breadth and ℓ be the length of the rectangle. Given: dtdA=−5,dtdℓ=2,dtdb=−3 We know, A=ℓ×b ⇒dtdA=ℓ⋅dtdb+b⋅dtdℓ=−3ℓ+2b⇒−5=−3ℓ+2b. When b=2, we have −5=−3ℓ+4⇒ℓ=39=3m
JEE Main 2012 — Mathematics Calculus
Consider a rectangle whose length is increasing at the uniform rate of 2 m/sec, breadth is decreasing at the uniform rate of 3 m/sec and the area is decreasing at the uniform rate of 5 m2/sec. If after some time the breadth of the rectangle is 2 m then the length of the rectangle is
Held on 12 May 2012 · Verified 6 Jul 2026.
2 m
4 m
1 m
3 m
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