dxdy=y+3⇒y+3dy=dx ln(y+3)=x+c x=0⇒y=2 ⇒ln5=0+c c=ln5 ln(y+3)=x+ln5 y+3=ex+ln5⇒y+3=eln2+ln5 y+3=10⇒y=7
If dxdy=y+3>0 and y(0)=2, then y(ln2) is equal to
Held on 30 Apr 2011 · Verified 6 Jul 2026.
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