Match List-I with List-II | List-I | List-II | |---|---| | (A) An observed set of population selected for analysis | (I) Parameter | | (B) A specific characteristic of the population | (II) Hypothesis | | (C) A specific characteristic of the sample | (III) Statistic | | (D) A statement made about a population parameter for testing | (IV) Sample | Choose the correct answer from the options given below:

Match List-I with List-II | List-I | List-II | |---|---| | (A) An observed set… - CUET UG 2025 Mathematics PYQ

CUET UG 2025 — Mathematics Statistics & Applications

2025mcqmedium

Match List-I with List-II

List-I	List-II
(A) An observed set of population selected for analysis	(I) Parameter
(B) A specific characteristic of the population	(II) Hypothesis
(C) A specific characteristic of the sample	(III) Statistic
(D) A statement made about a population parameter for testing	(IV) Sample

Choose the correct answer from the options given below:

Official previous-year question

Held on 14 May 2025 · Verified 13 Jul 2026.

Options

A
(A) - (I), (B) - (II), (C) - (III), (D) - (IV)
B
(A) - (IV), (B) - (III), (C) - (I), (D) - (II)
C
(A) - (I), (B) - (II), (C) - (IV), (D) - (III)
D
(A) - (IV), (B) - (I), (C) - (III), (D) - (II)

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Solution

Two dice are rolled simultaneously - a black die and a red die.

Given that the black die shows 5, we need to find the probability that the sum is greater than 9.

Since the black die is fixed at 5, only the red die outcome matters.

The sum is: Black die + Red die = 5 + Red die

For the sum to be greater than 9:

$5 + \text{Red die} > 9$

$\text{Red die} > 4$

A standard die shows values 1, 2, 3, 4, 5, 6.

The red die must show a value greater than 4.

Favorable outcomes: Red die shows 5 or 6

Number of favorable outcomes = 2

Total possible outcomes for red die = 6

$\text{Probability} = \dfrac{\text{Favorable outcomes}}{\text{Total possible outcomes}}$

$\text{Probability} = \dfrac{2}{6}$

$\text{Probability} = \dfrac{1}{3}$

Therefore, the probability of obtaining a sum greater than 9, given that the black die shows 5, is $\dfrac{1}{3}$ .

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