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Let two independent random samples of sizes n_1 and n_2 respectively have been drawn from the same normal population. Let X_1 and X_2 be the means…

CUET UG 2025 — Mathematics Statistics & Applications

2025mcqmedium

Let two independent random samples of sizes n1n_1n1​ and n2n_2n2​ respectively have been drawn from the same normal population. Let X1‾\overline{X_1}X1​​ and X2‾\overline{X_2}X2​​ be the means and let s1s_1s1​ and s2s_2s2​ be their standard deviations. In order to test whether the the two sample means X1‾\overline{X_1}X1​​ and X2‾\overline{X_2}X2​​ differ significantly or not, the ttt-test statistic is given by

Official previous-year question

Held on 15 May 2025 · Verified 13 Jul 2026.

Options

  1. A

    t=X1‾−X2‾S/1n1−1n2t = \frac{\overline{X_1} - \overline{X_2}}{S / \sqrt{\frac{1}{n_1} - \frac{1}{n_2}}}t=S/n1​1​−n2​1​​X1​​−X2​​​ , S=n1s12+n2s22n1+n2−2S = \sqrt{\frac{n_1 s_1^2 + n_2 s_2^2}{n_1 + n_2 - 2}}S=n1​+n2​−2n1​s12​+n2​s22​​​

  2. B

    t=X1‾−X2‾s/1n1+1n2t = \frac{\overline{X_1} - \overline{X_2}}{s /\sqrt{\frac{1}{n_1} + \frac{1}{n_2}}}t=s/n1​1​+n2​1​​X1​​−X2​​​ , S=n1s12+n2s22n1+n2−2S = \sqrt{\frac{n_1 s_1^2 + n_2 s_2^2}{n_1 + n_2 - 2}}S=n1​+n2​−2n1​s12​+n2​s22​​​

  3. C

    t=X1‾−X2‾S1n1+1n2t = \frac{\overline{X_1} - \overline{X_2}}{S \sqrt{\frac{1}{n_1} + \frac{1}{n_2}}}t=Sn1​1​+n2​1​​X1​​−X2​​​ , S=n1s12+n2s22n1+n2−2S = \sqrt{\frac{n_1 s_1^2 + n_2 s_2^2}{n_1 + n_2 - 2}}S=n1​+n2​−2n1​s12​+n2​s22​​​

  4. D

    t=X1‾+X2‾s1n1+1n2t = \frac{\overline{X_1} + \overline{X_2}}{s \sqrt{\frac{1}{n_1} + \frac{1}{n_2}}}t=sn1​1​+n2​1​​X1​​+X2​​​ , S=n1s12+n2s22n1+n2−2S = \sqrt{\frac{n_1 s_1^2 + n_2 s_2^2}{n_1 + n_2 - 2}}S=n1​+n2​−2n1​s12​+n2​s22​​​

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