The bag contains 8 blue balls and 12 green balls, for a total of 20 balls. Two balls are drawn in succession without replacement.
For the first draw, there are 20 balls total and 8 are blue.
P(1st Blue)=208
After drawing one blue ball, 19 balls remain in the bag. The 12 green balls are still in the bag.
P(2nd Green | 1st Blue)=1912
For both events to occur, multiply the probabilities:
P(Blue then Green)=208×1912
=38096
=9524
Therefore, the probability is 9524.