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If ∫ 2x - 5 (2x - 3)^3 e^2x dx = λ e^2x (2x - 3)^2 + C, where C is an arbitrary constant then the value of λ is

CUET UG 2025 — Mathematics Calculus

2025mcqmedium

If ∫2x−5(2x−3)3e2xdx=λe2x(2x−3)2+C\displaystyle \int \frac{2x - 5}{(2x - 3)^3} e^{2x} dx = \frac{\lambda e^{2x}}{(2x - 3)^2} + C∫(2x−3)32x−5​e2xdx=(2x−3)2λe2x​+C, where CCC is an arbitrary constant then the value of λ\lambdaλ is

Official previous-year question

Held on 22 May 2025 · Verified 13 Jul 2026.

Options

  1. A

    12\frac{1}{2}21​

  2. B

    2

  3. C

    -2

  4. D

    −12-\frac{1}{2}−21​

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