The region is bounded by the line 2y+x=8, the x-axis, and the vertical lines x=2 and x=4.
Solving for y:
2y+x=8
2y=8−x
y=28−x
y=4−2x
Finding the heights at the boundaries:
At x=2:
y=4−22
y=4−1
y=3
At x=4:
y=4−24
y=4−2
y=2
The region forms a trapezoid with:
- Left side height =3 units
- Right side height =2 units
- Width =4−2=2 units
Using the trapezoid area formula:
Area=21(b1+b2)×h
Area=21(3+2)×2
=21×5×2
=5
Therefore, the area of the bounded region is 5 square units.