Given x=et and y=e2t.
Since x=et, we have:
t=ln(x)
Substituting into the expression for y:
y=e2t
y=e2ln(x)
y=eln(x2)
y=x2
Taking the first derivative with respect to x:
dxdy=2x
Taking the second derivative with respect to x:
dx2d2y=dxd(2x)
dx2d2y=2
Therefore, dx2d2y=2