Rewrite denominator: x2(x4+1)3/4=x5(1+x41)3/4.
Let u=1+x41, du=−x54dx.
Integral =−41∫u−3/4du=−u1/4+C=−(x4x4+1)1/4+C.
The integral ∫x2(x4+1)43dx equals __________.
Held on 15 Jun 2023 · Verified 13 Jul 2026.
(x4x4+1)41+C
(x4+1)41+C
−(x4+1)41+C
−(x4x4+1)41+C
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