f(x)=x(x−1)(x+1)x−1=x(x+1)1 for x=1. Undefined at x=0,x=−1. At x=1: x→1limx(x+1)1=21=f(1)=1, so discontinuous. Total: three points.
The function f(x)=x(x2−1)x−1,x=1,f(1)=1, is discontinuous at
Held on 25 May 2023 · Verified 13 Jul 2026.
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