Rewrite: ∫sinxcosxtanxdx=∫tanxsec2xdx. Let u=tanx, du=sec2xdx. Integral becomes ∫udu=2u+c=2tanx+c.
CUET UG 2023 — Mathematics Calculus
Solution of differential equation xdy−ydx=0 respresents :
Held on 30 May 2023 · Verified 13 Jul 2026.
family of straight lines passing through origin
family of parabolas whose vertex is at origin
family of circles whose centre is at origin
family of straight lines passing through (1, 1)
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The derivative of x³ + 2x² - 5x + 1 is:
If the function $f(x) = 2x^3 + 9x^2 + 12x-1$ is given,then $f(x)$ have
If $\int \frac{dx}{(x-1)^3/^4. (x+2)^5/^4} = a[1 - g(x)]^b + c$, where $c$ is a constant of integration, then which of the following are true? (A) $a = \frac{2}{3}$ (B) $\beta = \frac{3}{4}$ (C) $3\alpha + 4\beta = 5$ (D) $g(x) = \frac{3}{(x+2)}$ Choose the **correct** answer from the options given below:
Match **List-I** with **List-II** | List-I | List-II | |---|---| | **Function** | **Increasing on the interval** | | (A) $f(x) = -x^2 - 2x + 1$ | (I) $(-\infty, -1)$ | | (B) $f(x) = x^2 + 1$ | (II) $(1, \infty)$ | | (C) $f(x) = x^2 - 2x + 3$ | (III) $(-\infty, 0)$ | | (D) $f(x) = -x^2$ | (IV) $(0, \infty)$ | Choose the correct answer from the options given below:
The integral $\int e^x\left(\frac{x-1}{2x^2}\right)dx$ is equal to
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