(A) y=log(sinx): y′′=−csc2x, IV.
(B) y=e1+logx=ex: y′′=0, III.
(C) y=log∣x∣: y′=1/x, y′′=−1/x2, I.
(D) y=x2+4x−1: y′′=2, II.
Match List - I with List - II.
| List - I | List - II | ||
|---|---|---|---|
| (A) | y=log(sinx) | (I) | dx2d2y=−x21 |
| (B) | y=e(1+logx) | (II) | dx2d2y=2 |
| (C) | y=log∣x∣ | (III) | dx2d2y=0 |
| (D) | y=x2+4x−1 | (IV) | dx2d2y=−csc2x |
Choose the correct answer from the options given below :
Held on 22 May 2023 · Verified 13 Jul 2026.
(A)-(I), (B)-(II), (C)-(III), (D)-(IV)
(A)-(II), (B)-(I), (C)-(IV), (D)-(III)
(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
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