f′(x)=21−x22=2x2x2−4. For decreasing, f′(x)<0⇒x2−4<0⇒−2<x<2, x=0. So decreasing on (−2,0)∪(0,2).
The interval in which f(x)=2x+x2 is a decreasing function of x is :
Held on 23 Aug 2022 · Verified 13 Jul 2026.
[−2,2]
(−∞,−2)∪(2,∞)
(−2,0)∪(0,2)
(−2,2)
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