Minor segment area =2∫5/2525−x2dx=2[2x25−x2+225sin−1(x/5)]5/25. Evaluating: at x=5, value is 225π; at x=5/2, value is 4575+625π. Difference =225π−625π−4253=325π−4253=1225(4π−33).
The area (in square units) of minor segment of the circle x2+y2=25 cut off by the line x=25 is
Held on 10 Aug 2022 · Verified 13 Jul 2026.
25(4π−23)
1225(4π−33)
1225(3π−43)
25(23+4π)
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