A: [1+(y′)2]2=y′′, degree of y′′ is 1 (III). B: square both sides: 1+(y′′)3=(y′)6, degree of y′′ is 3 (IV). C: highest order y′′′, degree 2 (I). D: square: 1+(y′)3=(y′′)4, degree of y′′ is 4 (II). Match: A-III, B-IV, C-I, D-II.
Match List - I with List - II
| List - I (Differential Equation) | List - II (Degree) |
|---|---|
| A. [1+(y′)2]2=y′′ | I. 2 |
| B. [1+(y′′)3]21=(y′)3 | II. 4 |
| C. (y′′′)2+y′′+3y′+5y=ex | III. 1 |
| D. [1+(y′)3]21=(y′′)2 | IV. 3 |
Choose the correct answer from the option given below:
Held on 23 Aug 2022 · Verified 13 Jul 2026.
A-III, B-I, C-II, D-IV
A-III, B-IV, C-I, D-II
A-II, B-III, C-IV, D-I
A-III, B-II, C-I, D-IV
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