y′=x2+11. So x2+1y′=1. Differentiating: x2+1xy′+x2+1y′′=0. Multiplying by x2+1: (x2+1)y′′+xy′=0. So a=1+x2, b=x, c=0. Correct: A, C, D.
Let y=log(x+x2+1), and adx2d2y+bdxdy=c. Then identify the correct statements about the values of a, b and c :
(A) a=1+x2
(B) b=0
(C) c=0
(D) b=x
(E) c=2
Choose the correct answer from the options given below :
Held on 17 Aug 2022 · Verified 13 Jul 2026.
(A), (B), (E) only
(A), (B), (C) only
(A), (C), (D) only
(A), (B), (D) only
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