Use the standard result ∫a2−u2du=2ua2−u2+2a2sin−1au+C.
Here 1−49x2=1−(7x)2. Let u=7x, du=7dx:
∫1−49x2dx=2x1−49x2+141sin−1(7x)+C.
∫1−49x2dx is equal to
Held on 30 Aug 2022 · Verified 13 Jul 2026.
2x(1−49x2)+981sin−17x+C
27x1+49x2+491sin−1x+C
2x1+7x21−491sin−17x+C
2x1−49x2+141sin−17x+C
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