cos2θ+3sin2θ−3sin2θ+2.
Using double angle formulas:
=21+cos2θ+23(1−cos2θ)−3sin2θ+2
=4−cos2θ−3sin2θ.
Minimum of −cos2θ−3sin2θ=−1+9=−10.
Least value =4−10.
JEE Main 2026 — Mathematics Trigonometry
The least value of (cos2θ−6sinθcosθ+3sin2θ+2) is
Held on 23 Jan 2026 · Verified 6 Jul 2026.
−1
1
4−10
4+10
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