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Let cos (α+β)=- 1 10 and sin (α-β)= 3 8, where 0<α< π 3 and 0<β< π 4. If tan 2 α= 3(1-r √5) √11(s+√5), r, s ∈ N, then r+s is equal to ____ .

JEE Main 2026 — Mathematics Trigonometry

2026integerhard

Let cos⁡(α+β)=−110\cos (\alpha+\beta)=-\frac{1}{10}cos(α+β)=−101​ and sin⁡(α−β)=38\sin (\alpha-\beta)=\frac{3}{8}sin(α−β)=83​, where 0<α<π30<\alpha<\frac{\pi}{3}0<α<3π​ and 0<β<π40<\beta<\frac{\pi}{4}0<β<4π​. If tan⁡2α=3(1−r5)11(s+5),r,s∈N\tan 2 \alpha=\frac{3(1-r \sqrt{5})}{\sqrt{11}(s+\sqrt{5})}, r, s \in Ntan2α=11​(s+5​)3(1−r5​)​,r,s∈N, then r+sr+sr+s is equal to ____\_\_\_\_____ .

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Held on 22 Jan 2026 · Verified 6 Jul 2026.

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