For cos−1(11−3x2x−5): −1≤11−3x2x−5≤1 gives x≤516 or x>6.
For sin−1(2x2−3x+1): −1≤2x2−3x+1≤1.
Lower bound always satisfied (discriminant <0).
Upper bound gives x(2x−3)≤0, so 0≤x≤23.
Intersection of both conditions: [0,23].
Thus α=0, β=23.
α+2β=0+3=3.