Skip to main content

The sum of all values of θ ∈[0,2 π] satisfying 2 sin ^2 θ=cos 2 θ and 2 cos ^2 θ=3 sin θ is

JEE Main 2025 — Mathematics Trigonometry

2025mcqeasy

The sum of all values of θ∈[0,2π]\theta \in[0,2 \pi]θ∈[0,2π] satisfying 2sin⁡2θ=cos⁡2θ2 \sin ^2 \theta=\cos 2 \theta2sin2θ=cos2θ and 2cos⁡2θ=3sin⁡θ2 \cos ^2 \theta=3 \sin \theta2cos2θ=3sinθ is

Official previous-year question

Held on 22 Jan 2025 · Verified 6 Jul 2026.

Options

  1. A

    4π4 \pi4π

  2. B

    5π6\frac{5 \pi}{6}65π​

  3. C

    π\piπ

  4. D

    π2\frac{\pi}{2}2π​

Did you get this right?

Sign in to track your attempts and accuracy.

Your note

Sign in to keep a private note on this question. Nothing you write is ever public.

JEE Main Trigonometry in other years

More JEE Main Trigonometry questions

Other Mathematics topics for JEE Main

Keep practicing Trigonometry

Work through every JEE Main Trigonometry PYQ, year by year.

Browse all Mathematics topics