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If 10 sin ^4 θ+15 cos ^4 θ=6, then the value of 27 cosec^6 θ+8 sec ^6 θ 16 sec ^8 θ is:

JEE Main 2025 — Mathematics Trigonometry

2025mcqeasy

If 10sin⁡4θ+15cos⁡4θ=610 \sin ^4 \theta+15 \cos ^4 \theta=610sin4θ+15cos4θ=6, then the value of 27cosec⁡6θ+8sec⁡6θ16sec⁡8θ\frac{27 \operatorname{cosec}^6 \theta+8 \sec ^6 \theta}{16 \sec ^8 \theta}16sec8θ27cosec6θ+8sec6θ​ is:

Official previous-year question

Held on 4 Apr 2025 · Verified 6 Jul 2026.

Options

  1. A

    25\frac{2}{5}52​

  2. B

    34\frac{3}{4}43​

  3. C

    35\frac{3}{5}53​

  4. D

    15\frac{1}{5}51​

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