sin−1(23x+211−x2),2−1<x<21⇒ Let sin−1(x)=θ6−π<θ<4π⇒x=sinθ, then ⇒sin−1(23sinθ+21cosθ)⇒sin−1(sin(θ+6π))=θ+6π⇒sin−1(x)+6π
Considering the principal values of the inverse trigonometric functions, sin−1(23x+211−x2),−21<x<21, is equal to
Held on 4 Apr 2025 · Verified 6 Jul 2026.
4π+sin−1x
6π+sin−1x
6−5π−sin−1x
65π−sin−1x
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