I=∫1/43/4cos(2cot−1(1+x1−x)dx)∫1/43/4cos(2(tan−11+x1+x))dx∫1/43/41+tan2(tan−11−x1+x1−tan2(tan−11−x1+x)dx =∫1/43/41+(1−x1+x)1−(1−x1+x)dx=∫1/43/42−2xdx=∫1/43/4(−x)dx=−(2x2)1/43/4=−21[169−161]=−41
The integral ∫1/43/4cos(2cot−11+x1−x)dx is equal to
Held on 9 Apr 2024 · Verified 6 Jul 2026.
1/2
−1/2
−1/4
1/4
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