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If a= sin^-1( sin(5)) and b= cos^-1( cos(5)), then a^2+b^2 is equal to

JEE Main 2024 — Mathematics Trigonometry

2024mcqeasy

If a=sin−1(sin(5))a={\mathrm{sin}}^{-1}(\mathrm{sin}(5))a=sin−1(sin(5)) and b=cos−1(cos(5))b={\mathrm{cos}}^{-1}(\mathrm{cos}(5))b=cos−1(cos(5)), then a2+b2{a}^{2}+{b}^{2}a2+b2 is equal to

Official previous-year question

Held on 31 Jan 2024 · Verified 6 Jul 2026.

Options

  1. A

    4π2+254{\pi }^{2}+254π2+25

  2. B

    8π2−40π+508{\pi }^{2}-40\pi +508π2−40π+50

  3. C

    4π2−20π+504{\pi }^{2}-20\pi +504π2−20π+50

  4. D

    252525

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