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Let S be the set of all solutions of the equation cos^-1(2x)-2 cos^-1(√1-x^2)=π ,x∈ [- 1 2, 1 2]. Then undersetx∈ S Σ 2 sin^-1(x^2-1) is equal to

JEE Main 2023 — Mathematics Trigonometry

2023mcqhard

Let SSS be the set of all solutions of the equation cos−1(2x)−2cos−1(1−x2)=π,x∈[−12,12]{\mathrm{cos}}^{-1}(2x)-2{\mathrm{cos}}^{-1}(\sqrt{1-{x}^{2}})=\pi ,x\in [-\frac{1}{2},\frac{1}{2}]cos−1(2x)−2cos−1(1−x2​)=π,x∈[−21​,21​]. Then ∑x∈S2sin−1(x2−1)\displaystyle \underset{x\in S}{\sum }2{\mathrm{sin}}^{-1}({x}^{2}-1)x∈S∑​2sin−1(x2−1) is equal to

Official previous-year question

Held on 1 Feb 2023 · Verified 6 Jul 2026.

Options

  1. A

    000

  2. B

    −2π3\frac{-2\pi }{3}3−2π​

  3. C

    π−sin−1(34)\pi -{\mathrm{sin}}^{-1}(\frac{\sqrt{3}}{4})π−sin−1(43​​)

  4. D

    π−2sin−1(34)\pi -2{\mathrm{sin}}^{-1}(\frac{\sqrt{3}}{4})π−2sin−1(43​​)

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