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The general solution of sin²θ - 2cosθ + 1/4 = 0 is:

JEE Main 2023 — Mathematics Trigonometry

2023mcqhard

The general solution of sin²θ - 2cosθ + 1/4 = 0 is:

Official previous-year question

Verified 30 May 2026.

Options

  1. A

    θ = 2nπ ± π/3

  2. B

    θ = 2nπ ± π/6

  3. C

    θ = nπ ± π/3

  4. D

    θ = nπ + (-1)ⁿπ/6

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