To find ⇒2sin12∘−sin72
⇒sin12∘+sin12∘−sin72
⇒sin12∘+2cos42∘sin(−30∘) ⇒sin12∘−cos42∘
⇒sin12∘−sin48∘ ⇒2cos(30∘)sin(−18∘)
⇒−3sin18∘=−3(45−1) =3(41−5)
JEE Main 2022 — Mathematics Trigonometry
The value of 2sin12∘−sin72∘ is
Held on 25 Jun 2022 · Verified 6 Jul 2026.
45(1−3)
81−5
23(1−5)
43(1−5)
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