Given, sin−1(sin32π)+cos−1(cos67π)+tan−1tan(43π)
Now simplifying each term we get,
sin−1sin(32π)=π−32π=3π
cos−1(cos67π)=2π−67π=65π
tan−1tan(43π)=43π−π=4−π
sin−1(sin32π)+cos−1cos67π+tan−1tan43π
=3π+65π−4π
=1211π
sin−1(sin32π)+cos−1(cos67π)+tan−1(tan43π) is equal to
Held on 27 Jun 2022 · Verified 6 Jul 2026.
1211π
1217π
1231π
−43π
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