We have,
tan(2tan−1(53)+sin−1(135))
=tan(tan−1(53)+tan−1(53)+sin−1(135))
=tan(tan−1(1−25953+53)+sin−1(135))
=tan(tan−1(815)+tan−1(125))
=tan−1[1−815⋅125815+125]=tan−121220
=tan(tan−121220)=21220
The value of tan(2tan−1(53)+sin−1(135)) is equal to:
Held on 20 Jul 2021 · Verified 6 Jul 2026.
69−181
21220
76−291
63151
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