Given,
sinx+sin2x+sin3x+sin4x=0
⇒(sinx+sin4x)+(sin2x+sin3x)=0
⇒2sin25xcos23x+2sin25xcos2x=0
⇒2sin25xcos23x+cos2x=0
⇒2sin25x2cosxcos2x=0
2sin25x=0⇒25x=0,π,2π,3π,4π,5π
⇒x=0,52π,54π,56π,58π,2π
and cos2x=0⇒2x=2π⇒x=π
and cosx=0⇒x=2π,23π
So sum =6π+π+2π=9π