sin−1(1312)−sin−1(53)
=tan−1(512)−tan−1(43) [sin−1x=tan−1(1−x2x)]
=tan−1(1+5×412×3512−43)
=tan−1(5633)
=sin−1(6533)
=cos−1(6556)=2π−sin−1(6556)
The value of sin−1(1312)−sin−1(53) is equal to:
Held on 12 Apr 2019 · Verified 6 Jul 2026.
π−cos−1(6533)
2π−cos−1(659)
π−sin−1(6563)
2π−sin−1(6556)
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