Skip to main content

The maximum value of 3 cos⁡θ +5 sin⁡(θ - π 6) for any real value of θ is :

JEE Main 2019 — Mathematics Trigonometry

2019mcqeasy

The maximum value of 3cos⁡θ+5sin⁡(θ−π6)3\mathrm{cos}⁡\theta +5\mathrm{sin}⁡(\theta -\frac{\pi }{6})3cos⁡θ+5sin⁡(θ−6π​) for any real value of θ\thetaθ is :

Official previous-year question

Held on 12 Jan 2019 · Verified 6 Jul 2026.

Options

  1. A

    19\sqrt{19}19​

  2. B

    31\sqrt{31}31​

  3. C

    792\frac{\sqrt{79}}{2}279​​

  4. D

    34\sqrt{34}34​

Did you get this right?

Sign in to track your attempts and accuracy.

Your note

Sign in to keep a private note on this question. Nothing you write is ever public.

JEE Main Trigonometry in other years

More JEE Main Trigonometry questions

Other Mathematics topics for JEE Main

Keep practicing Trigonometry

Work through every JEE Main Trigonometry PYQ, year by year.

Browse all Mathematics topics