sinx−sin2x+sin3x=0
⇒sinx+sin3x−sin2x=0
⇒2sin2x.cosx−sin2x=0
⇒sin2x=0 or cosx=21
⇒2x=0 or x=3π
⇒x=0 or x=3π
∴ Number of solutions =2
JEE Main 2019 — Mathematics Trigonometry
If 0≤x<2π, then the number of values of x for which sinx−sin2x+sin3x=0, is:
Held on 9 Jan 2019 · Verified 6 Jul 2026.
4
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2
1
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