cos(α+β)=53⇒tan(α+β)=34
sin(α−β)=135⇒tan(α−β)=125
Now,
tan2α=tan((α+β)+(α−β))
=1−tan(α+β)tan(α−β)tan(α+β)+tan(α−β)
=1−34×12534+125=1663
If cos(α+β)=53,sin(α−β)=135 and 0<α,β<4π, then tan(2α) is equal to:
Held on 8 Apr 2019 · Verified 6 Jul 2026.
1621
5263
5233
1663
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