ba>1⇒∠A>∠B
A+B=120∘
⇒sinBsin(120∘−B)=2+3
⇒ 23cotB+21=2+3
⇒cotB=32(23+3)
⇒cotB=2+3
⇒B=15∘
Hence, (∠A,∠B)=(105∘,15∘)
In a ΔABC, ba=2+3, and ∠C=60∘. Then the ordered pair (∠A,∠B) is equal to:
Held on 10 Apr 2015 · Verified 6 Jul 2026.
(105∘,15∘)
(15∘,105∘)
(45∘,75∘)
(75∘,45∘)
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