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If cos ^-1 x-cos ^-1 y 2=α, then 4 x^2-4 x y cos α+y^2 is equal to

JEE Main 2005 — Mathematics Trigonometry

2005mcqmedium

If cos⁡−1x−cos⁡−1y2=α\cos ^{-1} x-\cos ^{-1} \frac{y}{2}=\alphacos−1x−cos−12y​=α, then 4x2−4xycos⁡α+y24 x^2-4 x y \cos \alpha+y^24x2−4xycosα+y2 is equal to

Official previous-year question

Held on 30 Apr 2005 · Verified 6 Jul 2026.

Options

  1. A

    2sin⁡2α2 \sin 2 \alpha2sin2α

  2. B

    4

  3. C

    4sin⁡2α4 \sin ^2 \alpha4sin2α

  4. D

    −4sin⁡2α-4 \sin ^2 \alpha−4sin2α

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