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The centre of a circle C is at the centre of the ellipse E: x^2 a^2+ y^2 b^2=1, a gt b. Let C pass through the foci F_1 and F_2 of E such that the…

JEE Main 2025 — Mathematics Coordinate Geometry

2025mcqeasy

The centre of a circle C is at the centre of the ellipse E:x2a2+y2b2=1,a>bE: \frac{x^2}{a^2}+\frac{y^2}{b^2}=1, a \gt bE:a2x2​+b2y2​=1,a>b. Let CCC pass through the foci F1F_1F1​ and F2F_2F2​ of EEE such that the circle CCC and the ellipse EEE intersect at four points. Let P be one of these four points. If the area of the triangle PF1 F2\mathrm{PF}_1 \mathrm{~F}_2PF1​ F2​ is 30 and the length of the major axis of E is 17 , then the distance between the foci of E is :

Official previous-year question

Held on 4 Apr 2025 · Verified 6 Jul 2026.

Options

  1. A

    262626

  2. B

    131313

  3. C

    121212

  4. D

    132\frac{13}{2}213​

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