S1:x2+y2−2x−2y+1=0S2:x2+y2+2x−3=0 Common chord =S1−S2=0−4x−2y+4=02x+y=2⇒P(0,2)d(c,p)2=(1−0)2+(2−1)2=2
JEE Main 2024 — Mathematics Coordinate Geometry
Let the circle C1:x2+y2−2(x+y)+1=0 and C2 be a circle having centre at (−1,0) and radius 2 . If the line of the common chord of C1 and C2 intersects the y-axis at the point P, then the square of the distance of P from the centre of C1 is :
Held on 5 Apr 2024 · Verified 6 Jul 2026.
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